Two Cyclists Average Speed

Two cyclists rode from Prague to Poděbrady. Determine the average speed of each of them if you know that they traveled 56 km and that the slower one lost two kilometers to the faster one every hour so that he arrived in Poděbrady 30 minutes later.

Final Answer:

a =  16 km/h
b =  14 km/h

Step-by-step explanation:

56 = at 56 = b(t+30/60) a = 2+b  56 = (a2)(56/a+30/60) 56a=(a2)(56+0.5a)  0.5a2+a+112=0 0.5a2a112=0  p=0.5;q=1;r=112 D=q24pr=1240.5(112)=225 D>0  a1,2=2pq±D=11±225=1±151 a1,2=1±15 a1=16 a2=14  a=a1=16=16 km/h

Our quadratic equation calculator calculates it.

b=a2=162=14 km/h



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