Assignment 24071

1) Adam lives 4 kilometers from Eve. At the same time, he leaves for a meeting. Adam at a speed of 6 km/h and Eve at a speed of 4 km/h. How long will it take them to meet, and how many kilometers will Adam walk?

2) It was the same assignment, but Eva did not come out at the same time as Adam but 15 minutes later. How long before they meet, how many kilometers will Adam walk?

Correct answer:

t =  0.4 h
a =  2.4 km
t2 =  0.5667 h
a2 =  3.4 km

Step-by-step explanation:

v1=6 km/h v2=4 km/h  4=v1 t+v2 t 4=6 t+4 t  10t=4  t=104=0.4  t=52=0.4=0.4 h
a=v1 t=6 0.4=2.4 km
4=v1 t2+v2 (t15/60) 4=6 t2+4 (0.415/60)  360t2=204  t2=360204=0.56666667  t2=30170.566667=0.5667 h
a2=v1 t2=6 0.5667=3.4 km



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