The truck

The empty truck left the warehouse for goods at 10:00 and arrived at 11:30. At 2:00 pm, they loaded back on the same route. But it was a quarter slower than going to the warehouse. We know that on the way to the warehouse, the car was traveling at a speed 15km/h higher than the way back. Find the total length of the journey of the truck to the warehouse and back.

Correct result:

a =  60 km/h
s =  180 km

Solution:

$$\begin{gathered} b=a-a\mathrm{/}4 \\ a=15+b \\ 3a-4b=0 \\ a-b=15 \\ a=60 \\ b=45 \\ a=60=60\text{ km/h} \end{gathered}$$

$$\begin{gathered} t=11.50-10.00=1.5\text{ h } \\ {s}_1=a\cdot t=60\cdot 1.5=90\text{ km } \\ s=2\cdot s_1=2\cdot 90=180\text{ km} \end{gathered}$$

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