Timetable 2

A train runs according to a regular schedule from city A to city B, 270 km away, in 3 hours. On Monday, the train left city A with a delay of 18 minutes, but it arrived in city B according to the schedule. How many km/h was the average speed of the train on Monday higher than the train that ran according to the schedule?

Correct answer:

v =  10 km/h

Step-by-step explanation:

s=270 km t1=3 h t2=t118/60=318/60=1027=2.7 h  v1=s/t1=270/3=90 km/h v2=s/t2=270/2.7=100 km/h  v=v2v1=10090=10 km/h



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