A bus

A bus is scheduled to travel a distance 121 km in 2 3/4 hours. What average rate of speed must be maintained to arrive on schedule?

Correct result:

v =  44 km/h

Solution:

$$\begin{gathered} s=121\text{ km } \\ t=2{\displaystyle \frac{3}{4}}={\displaystyle \frac{2\cdot 4+3}{4}}={\displaystyle \frac{11}{4}}=2.75\text{ h } \\ v=s\mathrm{/}t=121\mathrm{/}2.75=44\text{ km/h} \end{gathered}$$

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