A bus

A bus is scheduled to travel a distance 121 km in 2 3/4 hours. What average rate of speed must be maintained to arrive on schedule?

Correct result:

v =  44 km/h

Solution:

s=121 km t=234=2⋅ 4+34=114=2.75 h  v=s/t=121/2.75=44 km/h

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