A bus

A bus is scheduled to travel a distance 121 km in 2 3/4 hours. What average rate of speed must be maintained to arrive on schedule?

Correct answer:

v =  44/1 = 44 km/h

Step-by-step explanation:

s=121 km t=243=2+43=42 4+3=411=2.75 h  v=s/t=121/2.75=44 km/h

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