Aircraft

Flight length 3457 km took 5 hours. The airport passengers had to arrive hours in advance, 2 hours. Departure was delayed for 6.4 hours. The destination airport formalities took 0.4 hours.

Calculate the average speed of passenger travel from arrival to leaving the airport.

Correct answer:

v =  250.5 km/h

Step-by-step explanation:

$v={\displaystyle \frac{3457}{5+2+6.4+0.4}}=250.5\text{ km/h}$

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