Train

A passenger train traveled for 2 hours 74 km. 3.1 hours after its departure started fast train and caught it on 186 km.

How many km/h is different its average speeds?

Correct result:

Δv =  59.52 km/h

Solution:

$$\begin{gathered} v_1=74\mathrm{/}2=37km\mathrm{/}h \\ {s}_1=s_2=186km \\ {v}_1(t+3.1)=v_{2}t=186km \\ t=186\mathrm{/}{v}_1-3.1=186\mathrm{/}37-3.1=1.93h \\ {v}_2=186\mathrm{/}t=96.52km\mathrm{/}h \\ \mathrm{\Delta }v=v_2-v_1=96.52-37=59.52\text{ km/h} \end{gathered}$$

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