Train

A passenger train traveled for 2 hours 74 km. 3.1 hours after its departure started fast train and caught it on 186 km.

How many km/h is different its average speeds?

Result

Δv =  59.52 km/h

Solution:

$v_1 = 74/2 = 37 \ km/h \ \\ \ \\ s_1 = s_2 = 186\ km \ \\ \ \\ v_1(t+3.1) = v_2 t = 186\ km \ \\ \ \\ t = 186/ v_1 -3.1 = 186/ 37 -3.1 = 1.93 \ h \ \\ \ \\ v_2 = 186/t = 96.52 \ km/h \ \\ \ \\ \Delta v = v_2 - v_1 = 96.52 - 37 = 59.52 \ \text{km/h}$

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