A passenger train traveled for 2 hours 74 km. 3.1 hours after its departure started fast train and caught it on 186 km.

How many km/h is different from its average speed?

Correct answer:

Δv =  59.52 km/h

Step-by-step explanation:

v1=74/2=37 km/h  s1=s2=186 km  v1(t+3.1)=v2t=186 km  t=186/v13.1=186/373.1=1.93 h  v2=186/t=96.52 km/h  Δv=v2v1=96.5237=59.52 km/h

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