Two trains meet

From A started at 7:15 express train at speed 85 km/h to B. From B started passenger train at 8:30 in the direction to A and at speed 55 km/h. The distance A and B are 386 1/4 km. At what time and at what distance from B the two trains meet?

Result

t = 10:30
b =  110 km

Solution:

a = 85(t-(7+15/60))
b = 55(t-(8+30/60))
a+b=386+1/4

a = 85•(t-(7+15/60))
b = 55•(t-(8+30/60))
a+b=386+1/4

60a-5100t = -36975
60b-3300t = -28050
4a+4b = 1545

a = 1105/4 = 276.25
b = 110
t = 21/2 = 10.5

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