Two trains meet

From A started at 7:15, express train at speed 85 km/h to B. From B started the passenger train at 8:30 in the direction to A and at a speed of 55 km/h. The distance A and B are 386 1/4 km. At what time and at what distance from B do the two trains meet?


t = 10:30 hh:mm Wrong answer
b =  110 km

Step-by-step explanation:

v1=85 km/h t1=7:15=7 hr 15 min =7+6015=7.25 hr=7.25 v2=55 km/h t2=8:30=8 hr 30 min =8+6030=8.5 hr=8.5 s=38641=386+41=4386 4+1=41544+1=41545=386.25 lm  a+b=s a=v1 (tt1) b=v2 (tt2) a+b=386.25 a=85 (t7.25) b=55 (t8.5)  a+b=386.25 a85t=616.25 b55t=467.5  Row2Row1Row2 a+b=386.25 b85t=1002.5 b55t=467.5  Row3+Row2Row3 a+b=386.25 b85t=1002.5 140t=1470  t=1401470=10.5 b=11002.5+85t=11002.5+85 10.5=110 a=386.25b=386.25110=276.25  a=41105=276.25 b=110 t=221=10.5=10:30 hh:mm

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