Trains for people

It is said that the train is synonymous to delay. Calculate the average speed of travel by train long 85 km, with regular train leave at 7:00 and arrive at 8:18, but train is late and has departure at 8:10 and arrive at 9:27.

Result

v =  34.6 km/h

Solution:

$s=85 \ \text{km} \ \\ t=9:27 - 7:00 \ \\ t=9.4576923-7 \doteq 2.4577 \ \text{h} \ \\ \ \\ v=\dfrac{ s }{ t }=\dfrac{ 85 }{ 2.4577 } \doteq 34.5853 \doteq 34.6 \ \text{km/h}$

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