Trains for people

It is said that the train is synonymous to delay. Calculate the average speed of travel by train long 85 km, with regular train leave at 7:00 and arrive at 8:18, but train is late and has departure at 8:10 and arrive at 9:27.

Correct result:

v =  34.6 km/h

Solution:

$$\begin{gathered} s=85\text{ km } \\ t=9:27-7:00 \\ t=9.4576923-7\doteq 2.4577\text{ h } \\ v={\displaystyle \frac{s}{t}}={\displaystyle \frac{85}{2.4577}}=34.6\text{ km/h} \end{gathered}$$

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