Train delay

Due to a breakdown, the train lost 16 minutes of standing on the track behind Brno. He "eliminated" this delay so that after the start, the 80 km long section went at a speed 10 km/h higher than originally planned. What speed was it and what was it supposed to be?

Correct result:

v1 =  50 km/h
v2 =  60 km/h

Solution:

s=80 km v0=10 km/h t0=16 min h=16/60  h=0.26667 h  s=v1 t s=v2 (tt0) v2=v1+v0  s=v1 t s=v2 tv2 t0 v2=v1+v0  s=(v2v0) t s=v2 tv2 t0  s=v2 tv0 t s=v2 tv2 t0  80=v1 t 80=v2 (t16/60) v2=v1+10  80=v1 t; 80=(v1+v0) (t16/60) 80=v1 t+v0 t16/60 v116/60 v0   t=1.6 h  v1=s/t=80/1.6=50 km/h
v2=v1+v0=50+10=60 km/h



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