Much-expected 9871

The train travels at an average speed of 75 km/h. According to the timetable, he should be at the station in 11 minutes, but he still has 20 km to go. How much-expected delay will appear on the station information board?

Correct answer:

d =  5 min

Step-by-step explanation:

v=75 km/h t1=11 min h=11:60  h=0.18333 h  s=20 km  t2=s/v=20/75=1540.2667 h  d1=t2t1=0.26670.1833=1210.0833 h  d=d1 min=d1 60  min=0.0833 60  min=5 min=5 min

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