Train delay

The train should be in the station for 10 minutes. It still has 32 km left. What is the expected delay if the train travels in 2 minutes 3 km except for the last section where it is 2 km in 5 minutes.

Correct result:

t =  15 min

Solution:

t3=10 min s=32 km s1=s2=322=30 km s2=2 km t1=s1/3 2=30/3 2=20 min t2=5 min T=t1+t2=20+5=25 min t=Tt3=2510=15 mint_{3}=10 \ \text{min} \ \\ s=32 \ \text{km} \ \\ s_{1}=s - 2=32 - 2=30 \ \text{km} \ \\ s_{2}=2 \ \text{km} \ \\ t_{1}=s_{1} / 3 \cdot \ 2=30 / 3 \cdot \ 2=20 \ \text{min} \ \\ t_{2}=5 \ \text{min} \ \\ T=t_{1}+t_{2}=20+5=25 \ \text{min} \ \\ t=T - t_{3}=25 - 10=15 \ \text{min}



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