Train delay

The train should be in the station for 10 minutes. It still has 32 km left. What is the expected delay if the train travels in 2 minutes 3 km except for the last section where it is 2 km in 5 minutes.

Result

t =  15 min

Solution:

t3=10 min s=32 km s1=s2=322=30 km s2=2 km t1=s1/3 2=30/3 2=20 min t2=5 min T=t1+t2=20+5=25 min t=Tt3=2510=15=15  min t_{ 3 } = 10 \ min \ \\ s = 32 \ km \ \\ s_{ 1 } = s - 2 = 32 - 2 = 30 \ km \ \\ s_{ 2 } = 2 \ km \ \\ t_{ 1 } = s_{ 1 } / 3 \cdot \ 2 = 30 / 3 \cdot \ 2 = 20 \ min \ \\ t_{ 2 } = 5 \ min \ \\ T = t_{ 1 }+t_{ 2 } = 20+5 = 25 \ min \ \\ t = T - t_{ 3 } = 25 - 10 = 15 = 15 \ \text{ min }



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