The Subway train went between two stations that gradually accelerated for 26 seconds and reached a speed of 72 km/h. At this rate, it went 56 seconds. Then 16 seconds slowed to a stop. What was the distance between the stations?

Correct answer:

s =  1.5 km

Step-by-step explanation:

 s=s1+s2+s3 s=21a1t12+vt2+21a3t32 s=21t1v0t12+vt2+21t3v0t32 s=21vt1+vt2+21vt3 s=v(2t1+t2+2t3) s=360072(226+56+216)=1.5 km

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