Train slowing down

A train slowed from 90 km/h to 72 km/h in 5 seconds. What distance did it travel during this time?

Final Answer:

s =  112.5 m

Step-by-step explanation:

t=5 s v1​=90 km/h→ m/s=90:3.6  m/s=25 m/s v2​=72 km/h→ m/s=72:3.6  m/s=20 m/s  a=(v1​−v2​)/t=(25−20)/5=1 m/s2  s2​=21​⋅ a⋅ t2=21​⋅ 1⋅ 52=225​=12.5 m  s=v1​⋅ t−s2​=25⋅ 5−12.5=112.5 m

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