Missile 3

A missile penetrated an embankment to a depth of 1.2 m. What was its speed when it hit the surface of the embankment, if the missile's movement through the ground lasted 0.021 seconds and the motion was uniformly decelerated?

Final Answer:

v =  114.2857 m/s

Step-by-step explanation:

s=1.2 m t=0.021 s  s = 21 a t2  a=t22 s=0.02122 1.25442.1769 m/s2  v=a t=5442.1769 0.021=114.2857 m/s



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