Free fall

The elevator car weighing 720 kg, is torn off at the height of 125 m and begins to fall in a free fall. How much kinetic energy did the elevator car have when it hit the ground floor of the building when the free fall of the car lasted 5 s?

Correct answer:

E =  882.9 kJ

Step-by-step explanation:

m=720 kg h=125 m g=9.81 m/s2  h = 21 g t2  t=2 h/g=2 125/9.815.0482 s  v=g t=9.81 5.048249.5227 m/s  E1=21 m v2=21 720 49.52272=882900 J  E=E1 kJ=E1:1000  kJ=882900:1000  kJ=882.9 kJ=108829 kJ=882.9 kJ

Did you find an error or inaccuracy? Feel free to write us. Thank you!

Tips for related online calculators
Do you want to convert velocity (speed) units?
Do you want to convert time units like minutes to seconds?

You need to know the following knowledge to solve this word math problem:

    Units of physical quantities:

    Themes, topics:

    Grade of the word problem:

    Related math problems and questions: