Free fall

The elevator car weighing 720 kg is torn off at a height of 125 m and begins to fall in a free fall. How much kinetic energy does the elevator car have when it hits the ground floor of the building, when the free fall of the car lasted 5 s?

Correct answer:

E =  882.9 kJ

Step-by-step explanation:

m=720 kg h=125 m g=9.81 m/s2  h=12gt2  t=2 h/g=2 125/9.815.0482 s  v=g t=9.81 5.048249.5227 m/s  E1=12 m v2=12 720 49.52272882900 J  E=E1 kJ=E1/1000  kJ=882900/1000  kJ=882.9 kJ=882910 kJ=882.9 kJ



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