Train speed

The train speed is decreased during 50 sec from 72 km/h to 36 km/h. Assuming that the train movement is equally slowing, find the the acceleration and the distance that it travels at.

Correct result:

a =  -0.2 m/a2
s =  750 m

Solution:

t=50 s v1=72 km/h m/s=72/3.6  m/s=20 m/s v2=36 km/h m/s=36/3.6  m/s=10 m/s  a=v2v1t=102050=15=15 m/a2=0.2 m/a2
s=v1 t+12 a t2=20 50+12 (0.2) 502=750 m



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