Two cars

Two cars, spaced d1 = 500 m apart, start moving against each other at time t1 = 0, the first car with acceleration a1 = 4 m/s ^ 2 and the second with acceleration a2 = 6 m/s ^ 2. At what time t2 do they meet? What distances s1 and s2 will they move from the start to the moment of meeting both cars?

Correct result:

t2 =  10 s
s1 =  200 m
s2 =  300 m


d1=500 m a1=4 m/s2 a2=6 m/s2  s1=12 a1 t22 s2=12 a2 t22  d1=s1+s2  d1=12 a1 t22+12 a2 t22  t2=2 d1a1+a2=2 5004+6=10 s
s1=12 a1 t22=12 4 102=200 m
s2=12 a2 t22=12 6 102=300 m

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