Personally 28573

At 9:00 a.m., a truck left town A at an average speed of 50 km/h to town B, 290 km from town A. In 1 hour and 20 minutes, a car drove behind him at an average speed of 75 km/h. At what time and distance from city B will the passenger truck catch?

Result

t = 12:07 hh:mm Wrong answer
s2 =  134 km

Step-by-step explanation:

t1=9.00 h t2=1:20=1 hr 20 min =1+6020=1.3333 hr1.3333 t3=t1+t2=9+1.3333=33110.3333 h  s1+s2 = s s=290 km v1=50 km/h v2=75 km/h  v1 (xt1)+v2 (xt3)=s 50 (x9)+75 (x10.333333333333)=290  125x=1515  x=1251515=12.12  x=25303=12.12  t=x=12.12=12:07 hh:mm
s2=sv1 (xt1)=29050 (12.129)=134 km



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