# Laboratory

Mang Elio went to his laboratory at 7:00am
And recorded that the temperature was 11.07°C. At lunchtime, the temperature rose by 27.9°C but dropped by 8.05°C at 5:00 PM. What was the temperature at 5:00 PM?

Correct result:

t =  30.92 °C

#### Solution:

$t=11.07+27.9-8.05=\frac{773}{25}={\frac{773}{25}}^{\circ }\text{C}=30.9{2}^{\circ }\text{C}$

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