Hard equations

If a<b and c<d and a+b all/2 = c and c+d all/2 = b and if d-a = 60, what is b-c?

Correct answer:

s =  20

Step-by-step explanation:

(a+b)/2=c (c+d)/2=b da=60  a+b=2c c+d=2b da=60  d=a+60 b=a+40 c=a+20  s=bc s=a+40(a+20)=a+40a20  s=4020=20



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