L Hospital's rule

Use L Hospital's rule to solve
(i) Lim x2+5x-14/x2-5x+6
X—>2
(ii)Lim x3+x2-x-1/x2-2x-3
X—>3

Correct answer:

a =  -9
b =  INF

Step-by-step explanation:

x1​=2 n1​=x12​+5⋅ x1​−14=22+5⋅ 2−14=0 d1​=x12​−5⋅ x1​+6=22−5⋅ 2+6=0   lim 0/0  ( x2+5x−14/x2−5x+6)′ = (2x+5) (x2−5⋅ x+6)′ = (2x−5)  a=2⋅ x1​−52⋅ x11​+5​=2⋅ 2−52⋅ 21+5​=−9
x2​=3 n2​=x23​+x22​−x2​−1=33+32−3−1=32 d2​=x22​−2⋅ x2​−3=32−2⋅ 3−3=0   lim 32/0  b=∞=INF

Try another example


Did you find an error or inaccuracy? Feel free to write us. Thank you!







You need to know the following knowledge to solve this word math problem:

algebrabasic operations and conceptsGrade of the word problem

Related math problems and questions: