Mr. Quick

Mr. Rychlý needs to drive from Brno to Prague. There is an oversized load on the D1 motorway, which leaves Brno at 11:00 p.m. at a speed of 12 km/h. What is the latest time Mr. Rychlý can depart to avoid getting caught behind the load, i.e. to reach the Humpolec exit at the 110 km mark before the oversized load does, given that he expects an average speed of 120 km/h?

Result

t = 7:15 hh:mm Wrong answer

Step-by-step explanation:

s=110 km v1=12 km/h v2=120 km/h  s=s1=s2 t1=s/v1=110/12=6559.1667 h t2=s/v2=110/120=12110.9167 h t3=2423.00=1 h  t=t1t3t2=9.166710.9167=7.25=7:15 hh:mm



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