Uphill and downhill

The cyclist moves uphill at a constant speed of v1 = 10 km/h. When he reaches the top of the hill, he turns and passes the same track downhill at a speed of v2 = 40 km/h. What is the average speed of a cyclist?

Correct result:

v =  16 km/h

Solution:

v1=10 km/h v2=40 km/h   s=v1 t1=v2 t2  t2=v1v2 t1  v=s+st1+t2=v1 t1+v2 t2t1+t2  v=v1 t1+v2 v1v2 t1t1+v1v2 t1  v=v1+v2 v1v21+v1v2  v=v1+v11+v1v2=10+101+1040=16 km/h



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