A number 8

A number K is such that when it is divided by 27, 30, or 45, the remainder is 3. Find the smallest possible value of K

Final Answer:

K =  273

Step-by-step explanation:

27=33 30=235 45=325 LCM(27,30,45)=2335=270  a=LCM(27,30,45)=270  K=a+3=270+3=273



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