Individual 82186

The average height of a member of a family of five is 1.5m, the mode of their height is 1.2m and the median is 1.6m.
Find out the heights of individual members of this family if you know that they are integers in dm.

Correct answer:

a =  12 dm
b =  12 dm
c =  16 dm
d =  17 dm
e =  18 dm

Step-by-step explanation:

$$\begin{gathered} m=1.5\text{m}\to \text{dm}=1.5\cdot 10\text{dm}=15\text{dm} \\ {m}_2=1.2\text{m}\to \text{dm}=1.2\cdot 10\text{dm}=12\text{dm} \\ {m}_3=1.6\text{m}\to \text{dm}=1.6\cdot 10\text{dm}=16\text{dm} \\ 1212161718 \\ a=12\text{dm} \\ b=a=12\text{dm} \\ c=16\text{dm} \\ d=c+1=16+1=17\text{dm} \\ e=d+1=17+1=18\text{dm} \\ \text{ Verifying Solution: } \\ M=\frac{a+b+c+d+e}{5}=\frac{12+12+16+17+18}{5}=15\text{dm} \end{gathered}$$

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