Saw a board

A board of 16 3-fourths inches is cut from a board that is 3 feet long. If the width of the saw cut is one-eighth inch, what is the length of the remaining piece?

Final Answer:

x =  19 ¹⁄₈ = 153/8 in

Step-by-step explanation:

$$\begin{gathered} a=3\text{ft}\to \text{in}=3\cdot 12\text{in}=36\text{in} \\ b=16\frac{3}{4}=16+\frac{3}{4}=\frac{16\cdot 4+3}{4}=\frac{64+3}{4}=\frac{67}{4}=16.75\text{in} \\ c=1/8=\frac{1}{8}=0.125\text{in} \\ x=a-b-c=36-\frac{67}{4}-\frac{1}{8}=\frac{153}{8}\text{in}=19\frac{1}{8}\text{in}=19.125\text{in} \end{gathered}$$

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