# Tiles

How many 46 cm square tiles will cover a floor 22.08 m by 8.74 m?

Result

n =  912

#### Solution:

$t = 46 \ cm = 46 / 100 \ m = 0.46 \ m \ \\ S_{ 1 } = 22.08 \cdot \ 8.74 = 192.9792 \ m^2 \ \\ S_{ 2 } = t^2 = 0.46^2 = \dfrac{ 529 }{ 2500 } = 0.2116 \ m^2 \ \\ \ \\ n = \dfrac{ S_{ 1 } }{ S_{ 2 } } = \dfrac{ 192.9792 }{ 0.2116 } = 912$

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Math student
where did you get 100?

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