Four-digit - sum

A four-digit number has a digit sum of 20. The sum of its last two digits is equal to the second digit increased by 5. The sum of the outer digits is equal to the second digit decreased by 3. If we write the digits of this number in reverse order, the number increases by 2178. Find this number.

Correct answer:

x =  1793

Step-by-step explanation:

x=abcd = 1000a+100b+10c + d a+b+c+d=20 c+d = b+5 a+d=b3 dcbaabcd=2178  a=0 , d=0 d>a da=2  c+d = b+5 a+d = b3 ac = 35 ac = 8  c = a+8 0 a,b,c,d9  0c=a+8 9 0a+8 9 80a98 1a1  a=1 c=a+8=1+8=9 d=a+2=1+2=3 b=20acd=20193=7  1+7+9+3=20 9+3 = 7+5 1+3=73 39711793=2178  x=1793



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