Area + perimeter TR2

Find the area of a triangle, two sides of which are 8 cm and 11 cm and whose perimeter is 32 cm.

Final Answer:

S =  43.8178 cm2

Step-by-step explanation:

a=8 cm b=11 cm c=32=13 cm o=32 cm  o=a+b+c  c=oab=32811=13 cm  s=2a+b+c=28+11+13=16 cm  S=s (sa) (sb) (sc)=16 (168) (1611) (1613)=8 30=43.8178 cm2



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arithmeticplanimetryUnits of physical quantitiesGrade of the word problem

 
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