Simple interest pa

If a sum of money doubles in 8 years at simple interest, in how many years will it become 3 times the original amount?

Final Answer:

t2 =  16

Step-by-step explanation:

t1=8 r1=2 r2=3  t1 (r01)=r11  r0=1+(r11)/t1=1+(21)/8=89=181=1.125 p0=12.5  %  t2 r0=r21  t2=(r21)/(r01)=(31)/(1.1251)=16



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algebraarithmeticbasic operations and conceptsUnits of physical quantitiesthemes, topicsGrade of the word problem

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