60-meter-long 8472

A 60-meter-long rope anchors the column at 3/4 of its height. The rope is anchored in the ground at a distance of 15 meters from the base of the column. Calculate the height of the column (in tenths).

Correct answer:

x =  77.4597 m

Step-by-step explanation:

$$\begin{gathered} c=60\text{m} \\ a=15\text{m} \\ {a}^2+(x\cdot 3/4{)}^2=c^2 \\ x=\frac{4}{3}\cdot \sqrt{c^2-a^2}=\frac{4}{3}\cdot \sqrt{60^2-15^2}=20\sqrt{15}=77.4597\text{m} \end{gathered}$$

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