Line slope calculator 9x-5y=-5
Straight line given by points A[0; 1] and B[5; 10]
Calculation:
Slope: m = 1.8Slope-intercept form of line: y = 1.8x+1
Canonical form of the line equation: 9x-5y+5 = 0
Parametric form of the line equation:
x = 5t
y = 9t+1 ; t ∈ R
Slope angle of line: φ = 60°56'43″ = 1.0637 rad
X intercept: x0 = -0.5556
Y intercept: y0 = q = 1
Distance line from the origin: d0 = 0.4856
The length of the segment AB: |AB| = 10.2956
Vector: AB = (5; 9)
Normal vector: n = (9; -5)
Midpoint of the segment AB: M = [2.5; 5.5]
Perpendicular Bisector equation: 5x+9y-62 = 0
Vector OA = (0; 1) ; |OA| = 1
Vector OB = (5; 10) ; |OB| = 11.1803
Scalar product OA .OB = 10
Angle ∠ AOB = 26°33'54″ = 0.4636 rad