Line slope calculator 3x-5y=-5
Straight line given by points A[0; 1] and B[5; 4]
Calculation:
Slope: m = 0.6Slope-intercept form of line: y = 0.6x+1
Canonical form of the line equation: 3x-5y+5 = 0
Parametric form of the line equation:
x = 5t
y = 3t+1 ; t ∈ R
Slope angle of line: φ = 30°57'50″ = 0.5404 rad
X intercept: x0 = -1.6667
Y intercept: y0 = q = 1
Distance line from the origin: d0 = 0.8575
The length of the segment AB: |AB| = 5.831
Vector: AB = (5; 3)
Normal vector: n = (3; -5)
Midpoint of the segment AB: M = [2.5; 2.5]
Perpendicular Bisector equation: 5x+3y-20 = 0
Vector OA = (0; 1) ; |OA| = 1
Vector OB = (5; 4) ; |OB| = 6.4031
Scalar product OA .OB = 4
Angle ∠ AOB = 51°20'25″ = 0.8961 rad