Line slope calculator x+8y=8
Straight line given by points A[0; 1] and B[8; 0]
Calculation:
Slope: m = -0.125Slope-intercept form of line: y = -0.125x+1
Canonical form of the line equation: x+8y-8 = 0
Parametric form of the line equation:
x = 8t
y = -t+1 ; t ∈ R
Slope angle of line: φ = -7°7'30″ = -0.1244 rad
X intercept: x0 = 8
Y intercept: y0 = q = 1
Distance line from the origin: d0 = 0.9923
The length of the segment AB: |AB| = 8.0623
Vector: AB = (8; -1)
Normal vector: n = (1; 8)
Midpoint of the segment AB: M = [4; 0.5]
Perpendicular Bisector equation: 8x-y-31.5 = 0
Vector OA = (0; 1) ; |OA| = 1
Vector OB = (8; 0) ; |OB| = 8
Scalar product OA .OB = 0
Angle ∠ AOB = 90° = 1.5708 rad