Line slope calculator 10x+y=10


Enter coordinates of two different points:

Straight line given by points A[0; 10] and B[1; 0]

Calculation:

Slope-intercept form of line: y = -10x+10

Canonical form of the line equation: 10x+y-10 = 0

Parametric form of the line equation:
x = t
y = -10t+10      ; t ∈ R

Slope: m = -10

Slope angle of line: φ = -84°17'22″ = -1.4711 rad

X intercept: x0 = 1

Y intercept: y0 = q = 10

Distance line from the origin: d0 = 0.995

The length of the segment AB: |AB| = 10.0499

Vector: AB = (1; -10)

Normal vector: n = (10; 1)

Midpoint of the segment AB: M = [0.5; 5]

Perpendicular Bisector equation: x-10y+49.5 = 0


Vector OA = (0; 10) ;   |OA| = 10
Vector OB = (1; 0) ;   |OB| = 1
Scalar product OA .OB = 0
Angle ∠ AOB = 90° = 1.5708 rad