Line slope calculator 9x+y=10
Straight line given by points A[0; 10] and B[1; 1]
Calculation:
Slope: m = -9Slope-intercept form of line: y = -9x+10
Canonical form of the line equation: 9x+y-10 = 0
Parametric form of the line equation:
x = t
y = -9t+10 ; t ∈ R
Slope angle of line: φ = -83°39'35″ = -1.4601 rad
X intercept: x0 = 1.1111
Y intercept: y0 = q = 10
Distance line from the origin: d0 = 1.1043
The length of the segment AB: |AB| = 9.0554
Vector: AB = (1; -9)
Normal vector: n = (9; 1)
Midpoint of the segment AB: M = [0.5; 5.5]
Perpendicular Bisector equation: x-9y+49 = 0
Vector OA = (0; 10) ; |OA| = 10
Vector OB = (1; 1) ; |OB| = 1.4142
Scalar product OA .OB = 10
Angle ∠ AOB = 45° = 0.7854 rad