Line slope calculator 8x+y=10


Enter coordinates of two different points:

Straight line given by points A[0; 10] and B[1; 2]

Calculation:

Slope-intercept form of line: y = -8x+10

Canonical form of the line equation: 8x+y-10 = 0

Parametric form of the line equation:
x = t
y = -8t+10      ; t ∈ R

Slope: m = -8

Slope angle of line: φ = -82°52'30″ = -1.4464 rad

X intercept: x0 = 1.25

Y intercept: y0 = q = 10

Distance line from the origin: d0 = 1.2403

The length of the segment AB: |AB| = 8.0623

Vector: AB = (1; -8)

Normal vector: n = (8; 1)

Midpoint of the segment AB: M = [0.5; 6]

Perpendicular Bisector equation: x-8y+47.5 = 0


Vector OA = (0; 10) ;   |OA| = 10
Vector OB = (1; 2) ;   |OB| = 2.2361
Scalar product OA .OB = 20
Angle ∠ AOB = 26°33'54″ = 0.4636 rad