Line slope calculator 6x+y=10


Enter coordinates of two different points:

Straight line given by points A[0; 10] and B[1; 4]

Calculation:

Slope-intercept form of line: y = -6x+10

Canonical form of the line equation: 6x+y-10 = 0

Parametric form of the line equation:
x = t
y = -6t+10      ; t ∈ R

Slope: m = -6

Slope angle of line: φ = -80°32'16″ = -1.4056 rad

X intercept: x0 = 1.6667

Y intercept: y0 = q = 10

Distance line from the origin: d0 = 1.644

The length of the segment AB: |AB| = 6.0828

Vector: AB = (1; -6)

Normal vector: n = (6; 1)

Midpoint of the segment AB: M = [0.5; 7]

Perpendicular Bisector equation: x-6y+41.5 = 0


Vector OA = (0; 10) ;   |OA| = 10
Vector OB = (1; 4) ;   |OB| = 4.1231
Scalar product OA .OB = 40
Angle ∠ AOB = 14°2'10″ = 0.245 rad