Line slope calculator 5x+y=10
Straight line given by points A[0; 10] and B[1; 5]
Calculation:
Slope: m = -5Slope-intercept form of line: y = -5x+10
Canonical form of the line equation: 5x+y-10 = 0
Parametric form of the line equation:
x = t
y = -5t+10 ; t ∈ R
Slope angle of line: φ = -78°41'24″ = -1.3734 rad
X intercept: x0 = 2
Y intercept: y0 = q = 10
Distance line from the origin: d0 = 1.9612
The length of the segment AB: |AB| = 5.099
Vector: AB = (1; -5)
Normal vector: n = (5; 1)
Midpoint of the segment AB: M = [0.5; 7.5]
Perpendicular Bisector equation: x-5y+37 = 0
Vector OA = (0; 10) ; |OA| = 10
Vector OB = (1; 5) ; |OB| = 5.099
Scalar product OA .OB = 50
Angle ∠ AOB = 11°18'36″ = 0.1974 rad