Line slope calculator 4x+y=10
Straight line given by points A[0; 10] and B[1; 6]
Calculation:
Slope: m = -4Slope-intercept form of line: y = -4x+10
Canonical form of the line equation: 4x+y-10 = 0
Parametric form of the line equation:
x = t
y = -4t+10 ; t ∈ R
Slope angle of line: φ = -75°57'50″ = -1.3258 rad
X intercept: x0 = 2.5
Y intercept: y0 = q = 10
Distance line from the origin: d0 = 2.4254
The length of the segment AB: |AB| = 4.1231
Vector: AB = (1; -4)
Normal vector: n = (4; 1)
Midpoint of the segment AB: M = [0.5; 8]
Perpendicular Bisector equation: x-4y+31.5 = 0
Vector OA = (0; 10) ; |OA| = 10
Vector OB = (1; 6) ; |OB| = 6.0828
Scalar product OA .OB = 60
Angle ∠ AOB = 9°27'44″ = 0.1651 rad