Line slope calculator 2x+y=10


Enter coordinates of two different points:

Straight line given by points A[0; 10] and B[1; 8]

Calculation:

Slope-intercept form of line: y = -2x+10

Canonical form of the line equation: 2x+y-10 = 0

Parametric form of the line equation:
x = t
y = -2t+10      ; t ∈ R

Slope: m = -2

Slope angle of line: φ = -63°26'6″ = -1.1071 rad

X intercept: x0 = 5

Y intercept: y0 = q = 10

Distance line from the origin: d0 = 4.4721

The length of the segment AB: |AB| = 2.2361

Vector: AB = (1; -2)

Normal vector: n = (2; 1)

Midpoint of the segment AB: M = [0.5; 9]

Perpendicular Bisector equation: x-2y+17.5 = 0


Vector OA = (0; 10) ;   |OA| = 10
Vector OB = (1; 8) ;   |OB| = 8.0623
Scalar product OA .OB = 80
Angle ∠ AOB = 7°7'30″ = 0.1244 rad