Line slope calculator 6x+10y=100


Enter coordinates of two different points:

Straight line given by points A[0; 10] and B[10; 4]

Calculation:

Slope-intercept form of line: y = -0.6x+10

Canonical form of the line equation: 6x+10y-100 = 0

Parametric form of the line equation:
x = 10t
y = -6t+10      ; t ∈ R

Slope: m = -0.6

Slope angle of line: φ = -30°57'50″ = -0.5404 rad

X intercept: x0 = 16.6667

Y intercept: y0 = q = 10

Distance line from the origin: d0 = 8.5749

The length of the segment AB: |AB| = 11.6619

Vector: AB = (10; -6)

Normal vector: n = (6; 10)

Midpoint of the segment AB: M = [5; 7]

Perpendicular Bisector equation: 10x-6y-8 = 0


Vector OA = (0; 10) ;   |OA| = 10
Vector OB = (10; 4) ;   |OB| = 10.7703
Scalar product OA .OB = 40
Angle ∠ AOB = 68°11'55″ = 1.1903 rad