Line slope calculator 10x+3y=30
Straight line given by points A[0; 10] and B[3; 0]
Calculation:
Slope: m = -3.3333Slope-intercept form of line: y = -3.3333x+10
Canonical form of the line equation: 10x+3y-30 = 0
Parametric form of the line equation:
x = 3t
y = -10t+10 ; t ∈ R
Slope angle of line: φ = -73°18'3″ = -1.2793 rad
X intercept: x0 = 3
Y intercept: y0 = q = 10
Distance line from the origin: d0 = 2.8735
The length of the segment AB: |AB| = 10.4403
Vector: AB = (3; -10)
Normal vector: n = (10; 3)
Midpoint of the segment AB: M = [1.5; 5]
Perpendicular Bisector equation: 3x-10y+45.5 = 0
Vector OA = (0; 10) ; |OA| = 10
Vector OB = (3; 0) ; |OB| = 3
Scalar product OA .OB = 0
Angle ∠ AOB = 90° = 1.5708 rad