Line slope calculator 8x+3y=30


Enter coordinates of two different points:

Straight line given by points A[0; 10] and B[3; 2]

Calculation:

Slope-intercept form of line: y = -2.6667x+10

Canonical form of the line equation: 8x+3y-30 = 0

Parametric form of the line equation:
x = 3t
y = -8t+10      ; t ∈ R

Slope: m = -2.6667

Slope angle of line: φ = -69°26'38″ = -1.212 rad

X intercept: x0 = 3.75

Y intercept: y0 = q = 10

Distance line from the origin: d0 = 3.5112

The length of the segment AB: |AB| = 8.544

Vector: AB = (3; -8)

Normal vector: n = (8; 3)

Midpoint of the segment AB: M = [1.5; 6]

Perpendicular Bisector equation: 3x-8y+43.5 = 0


Vector OA = (0; 10) ;   |OA| = 10
Vector OB = (3; 2) ;   |OB| = 3.6056
Scalar product OA .OB = 20
Angle ∠ AOB = 56°18'36″ = 0.9828 rad