Line slope calculator 8x+3y=30
Straight line given by points A[0; 10] and B[3; 2]
Calculation:
Slope: m = -2.6667Slope-intercept form of line: y = -2.6667x+10
Canonical form of the line equation: 8x+3y-30 = 0
Parametric form of the line equation:
x = 3t
y = -8t+10 ; t ∈ R
Slope angle of line: φ = -69°26'38″ = -1.212 rad
X intercept: x0 = 3.75
Y intercept: y0 = q = 10
Distance line from the origin: d0 = 3.5112
The length of the segment AB: |AB| = 8.544
Vector: AB = (3; -8)
Normal vector: n = (8; 3)
Midpoint of the segment AB: M = [1.5; 6]
Perpendicular Bisector equation: 3x-8y+43.5 = 0
Vector OA = (0; 10) ; |OA| = 10
Vector OB = (3; 2) ; |OB| = 3.6056
Scalar product OA .OB = 20
Angle ∠ AOB = 56°18'36″ = 0.9828 rad