Line slope calculator 7x+3y=30
Straight line given by points A[0; 10] and B[3; 3]
Calculation:
Slope: m = -2.3333Slope-intercept form of line: y = -2.3333x+10
Canonical form of the line equation: 7x+3y-30 = 0
Parametric form of the line equation:
x = 3t
y = -7t+10 ; t ∈ R
Slope angle of line: φ = -66°48'5″ = -1.1659 rad
X intercept: x0 = 4.2857
Y intercept: y0 = q = 10
Distance line from the origin: d0 = 3.9392
The length of the segment AB: |AB| = 7.6158
Vector: AB = (3; -7)
Normal vector: n = (7; 3)
Midpoint of the segment AB: M = [1.5; 6.5]
Perpendicular Bisector equation: 3x-7y+41 = 0
Vector OA = (0; 10) ; |OA| = 10
Vector OB = (3; 3) ; |OB| = 4.2426
Scalar product OA .OB = 30
Angle ∠ AOB = 45° = 0.7854 rad