Line slope calculator 4x+3y=30
Straight line given by points A[0; 10] and B[3; 6]
Calculation:
Slope: m = -1.3333Slope-intercept form of line: y = -1.3333x+10
Canonical form of the line equation: 4x+3y-30 = 0
Parametric form of the line equation:
x = 3t
y = -4t+10 ; t ∈ R
Slope angle of line: φ = -53°7'48″ = -0.9273 rad
X intercept: x0 = 7.5
Y intercept: y0 = q = 10
Distance line from the origin: d0 = 6
The length of the segment AB: |AB| = 5
Vector: AB = (3; -4)
Normal vector: n = (4; 3)
Midpoint of the segment AB: M = [1.5; 8]
Perpendicular Bisector equation: 3x-4y+27.5 = 0
Vector OA = (0; 10) ; |OA| = 10
Vector OB = (3; 6) ; |OB| = 6.7082
Scalar product OA .OB = 60
Angle ∠ AOB = 26°33'54″ = 0.4636 rad