Line slope calculator 6x+4y=40


Enter coordinates of two different points:

Straight line given by points A[0; 10] and B[4; 4]

Calculation:

Slope-intercept form of line: y = -1.5x+10

Canonical form of the line equation: 6x+4y-40 = 0

Parametric form of the line equation:
x = 4t
y = -6t+10      ; t ∈ R

Slope: m = -1.5

Slope angle of line: φ = -56°18'36″ = -0.9828 rad

X intercept: x0 = 6.6667

Y intercept: y0 = q = 10

Distance line from the origin: d0 = 5.547

The length of the segment AB: |AB| = 7.2111

Vector: AB = (4; -6)

Normal vector: n = (6; 4)

Midpoint of the segment AB: M = [2; 7]

Perpendicular Bisector equation: 4x-6y+34 = 0


Vector OA = (0; 10) ;   |OA| = 10
Vector OB = (4; 4) ;   |OB| = 5.6569
Scalar product OA .OB = 40
Angle ∠ AOB = 45° = 0.7854 rad