Line slope calculator 5x+4y=40
Straight line given by points A[0; 10] and B[4; 5]
Calculation:
Slope: m = -1.25Slope-intercept form of line: y = -1.25x+10
Canonical form of the line equation: 5x+4y-40 = 0
Parametric form of the line equation:
x = 4t
y = -5t+10 ; t ∈ R
Slope angle of line: φ = -51°20'25″ = -0.8961 rad
X intercept: x0 = 8
Y intercept: y0 = q = 10
Distance line from the origin: d0 = 6.247
The length of the segment AB: |AB| = 6.4031
Vector: AB = (4; -5)
Normal vector: n = (5; 4)
Midpoint of the segment AB: M = [2; 7.5]
Perpendicular Bisector equation: 4x-5y+29.5 = 0
Vector OA = (0; 10) ; |OA| = 10
Vector OB = (4; 5) ; |OB| = 6.4031
Scalar product OA .OB = 50
Angle ∠ AOB = 38°39'35″ = 0.6747 rad