Line slope calculator 5x+4y=40


Enter coordinates of two different points:

Straight line given by points A[0; 10] and B[4; 5]

Calculation:

Slope-intercept form of line: y = -1.25x+10

Canonical form of the line equation: 5x+4y-40 = 0

Parametric form of the line equation:
x = 4t
y = -5t+10      ; t ∈ R

Slope: m = -1.25

Slope angle of line: φ = -51°20'25″ = -0.8961 rad

X intercept: x0 = 8

Y intercept: y0 = q = 10

Distance line from the origin: d0 = 6.247

The length of the segment AB: |AB| = 6.4031

Vector: AB = (4; -5)

Normal vector: n = (5; 4)

Midpoint of the segment AB: M = [2; 7.5]

Perpendicular Bisector equation: 4x-5y+29.5 = 0


Vector OA = (0; 10) ;   |OA| = 10
Vector OB = (4; 5) ;   |OB| = 6.4031
Scalar product OA .OB = 50
Angle ∠ AOB = 38°39'35″ = 0.6747 rad