Line slope calculator 8x+5y=50
Straight line given by points A[0; 10] and B[5; 2]
Calculation:
Slope: m = -1.6Slope-intercept form of line: y = -1.6x+10
Canonical form of the line equation: 8x+5y-50 = 0
Parametric form of the line equation:
x = 5t
y = -8t+10 ; t ∈ R
Slope angle of line: φ = -57°59'41″ = -1.0122 rad
X intercept: x0 = 6.25
Y intercept: y0 = q = 10
Distance line from the origin: d0 = 5.3
The length of the segment AB: |AB| = 9.434
Vector: AB = (5; -8)
Normal vector: n = (8; 5)
Midpoint of the segment AB: M = [2.5; 6]
Perpendicular Bisector equation: 5x-8y+35.5 = 0
Vector OA = (0; 10) ; |OA| = 10
Vector OB = (5; 2) ; |OB| = 5.3852
Scalar product OA .OB = 20
Angle ∠ AOB = 68°11'55″ = 1.1903 rad