Line slope calculator 8x+5y=50


Enter coordinates of two different points:

Straight line given by points A[0; 10] and B[5; 2]

Calculation:

Slope-intercept form of line: y = -1.6x+10

Canonical form of the line equation: 8x+5y-50 = 0

Parametric form of the line equation:
x = 5t
y = -8t+10      ; t ∈ R

Slope: m = -1.6

Slope angle of line: φ = -57°59'41″ = -1.0122 rad

X intercept: x0 = 6.25

Y intercept: y0 = q = 10

Distance line from the origin: d0 = 5.3

The length of the segment AB: |AB| = 9.434

Vector: AB = (5; -8)

Normal vector: n = (8; 5)

Midpoint of the segment AB: M = [2.5; 6]

Perpendicular Bisector equation: 5x-8y+35.5 = 0


Vector OA = (0; 10) ;   |OA| = 10
Vector OB = (5; 2) ;   |OB| = 5.3852
Scalar product OA .OB = 20
Angle ∠ AOB = 68°11'55″ = 1.1903 rad